2 ms·
That would imply all sexual exclusive relationships are healthy, which is very much not the case. Sexual exclusivity and relationship health are orthogonal.
by Fargren 5y ago
That would imply all sexual exclusive relationships are healthy, which is very much not the case. Sexual exclusivity and relationship health are orthogonal.
- ethbr0 5y agoI think you're taking the set theory a bit too far...
- Fargren 5y agoThis might just be different customs of language usage. But to me, if you say "This is a subset of That", you are saying "every case of This is also a case of That". I suppose you are using it to mean "That does not imply This", and honestly I don't think seen it used that way elsewhere.
- ducharmdev 5y agoI mean, that is the immediate conclusion one can draw from what you're saying. It sounds like you're saying all sexually exclusive relationships are within the group of healthy relationships, which is different than saying only some of them are within that group.
- jjgreen 5y ago∀ X [ ∅ ∉ X ⟹ ∃ f : X → ⋃ X ∀ A ∈ X ( f ( A ) ∈ A ) ]