3 ms·
There sure is – one way is using the good ol' conditional operator: (x==3)?sin(i+t):0 Result: https://doersino.github.io/tixyz/?code=%28x%3D%3D3%29%3Fsin%28
by doersino 5y ago
There sure is – one way is using the good ol' conditional operator:
(x==3)?sin(i+t):0
Result: https://doersino.github.io/tixyz/?code=%28x%3D%3D3%29%3Fsin%28i%2Bt%29%3A0 https://doersino.github.io/tixyz/?code=%28x%3D%3D3%29%3Fsin%...
Another is multiplying with a boolean expression that's automatically cast to 0 or 1 depending on its value:
sin(i+t)*(x==3)
Result: https://doersino.github.io/tixyz/?code=sin%28i%2Bt%29*%28x%3D%3D3%29 https://doersino.github.io/tixyz/?code=sin%28i%2Bt%29*%28x%3...