9 ms·
Having read the title, I thought "hey, all you need is 2 measures". So the final constraint (not mentioned in the title) is to find out whether the anomalous b
by TomasSedovic 15y ago
Having read the title, I thought "hey, all you need is 2 measures".
So the final constraint (not mentioned in the title) is to find out whether the anomalous ball is heavier or lighter than the rest.
That's where the third measure comes in.
- shasta 15y agoBzz. You can't do what you claim in two weighings (gauranteed)
- TomasSedovic 15y agoSigh, you're right. Thank's for the correction. I guess it's true that nothing good happens after 2AM (my local time).
- tomp 15y agoNo way. Each experiment gives has 3 possible outcomes: left, right, and balanced. So in 2 experiments you can a maximum of 9 = 3*3 different outcomes. That's not enough to pick one ball out of 12. If you have 3 experiments, you have 27 outcomes. You need 24 to tell which ball, + heavier/lighter, and 3 outcomes are impossible. Edit: impossible or redundant, depending of your strategy.