6 ms·

Is that problematic in practice? Write functions that are pure or take references (not ownership), and for the rest, use a judicious .copy()?

• skohan 6y ago
  Yeah sure it's problematic. For instance, if you have a deeply nested struct, and you have to add a lifetime somewhere in the bottom, now you have to propagate it all the way up to the top level. Also if you run into a case where you need an explicit lifetime in a function somewhere, this ends up propagating outward. I've run into cases with Rust where I refactored a significant portion of a program to avoid nested references and explicit lifetimes in a way I haven't had to in other languages
  • fauigerzigerk 6y ago
    Yes, but you only have three choices basically: a) Accept the performance hit that comes with GC or defensive copying. b) Convince yourself that developers can keep all those potentially dangling references in their heads at all times. c) Use something like Rust lifetimes. My preference would be (a) whenever possible, (c) when absolutely necessary, and never (b)
    • zozbot234 6y ago
      You don't need GC or copying. Rust supports reference-counted handles that will never dangle, and will only leak in very rare cases involving self-referential data structures.
      • fauigerzigerk 6y ago
        I consider reference counting a form of GC - a rather slow one with lots of potential pitfalls.
        • nickez 6y ago
          It might be slow, but it is deterministic which is more important in systems programs.
          • Joker_vD 6y ago
            In what sense it is deterministic? Any refcount decrement may or may not be the last one and that may or may not cause a huge graph of objects being free()d which (even without destructors) takes unpredictable amount of time. Then again, malloc() itself is usually not deterministic in a sense that it may take an arbitrary amount of time to make an allocation: many implementations shift work from free() to malloc() to get better asymptotic time complexity.
            • pkolaczk 6y ago
              The problem of destructor chains has been solved a long time ago. You can deallocate on another thread or deallocate in small batches during allocations. Also pauses from malloc/free are orders of magnitude smaller than pauses caused by tracing GC. Low pause tracing GC creators make it a big news when they manage to get pauses below 1 ms, while malloc/free operate in range of tens or maybe hundreds nanoseconds. Tracing GC can pause a fragment of code that does not make any allocations. Refcounting can't. Refcounting has only local effects - you pay for it where you use it. But when you add tracing GC, its problems spread everywhere.
              • ghusbands 6y ago
                Delayed destruction (either on another thread or batches) removes the possibility of safely using RAII via finalizers, which removes one touted advantage of refcounting. Most modern implementations of refcounting end up having a cycle collector, anyway, which also means you can end up unexpectedly paused, removing another touted advantage. There are always trade-offs, so you can't really call any of it solved or make absolute claims. In general, GC implementations (including initially-refcounting) tend to converge over time in both performance and features.