3 ms·

This must surely fail... isn't it equivalent to solving the halting problem? Or does it run the whole program like a debugger?

• Quekid5 6y ago
  If false negatives are permitted the halting problem isn't an issue.
• Spivak 6y ago
  It fails pretty fast. import random y = 0 def f(x): print(x) if random.randint(0,1) == 2: y = 1 f(y) This not only fails but crashes the program.