4 ms·
No need for stacks of `..`. Use this instead: function up() { for i in $(seq 1 $1); do cd ..; done } # usage: up # goes up 1 directory up 2 # goes up 2 dire
by vaylian 6y ago
No need for stacks of `..`. Use this instead:
function up() { for i in $(seq 1 $1); do cd ..; done }
# usage:
up # goes up 1 directory
up 2 # goes up 2 directories
up 42 # goes up 42 directories
- sandreas 6y agoNice little helper function, thank you. What do you think about renaming it to '..'? For me this feels a bit more natural: function ..() { for i in $(seq 1 $1); do cd ..; done } .. # goes up 1 dir .. 2 # goes up 2 dirs .. 42 # goes up 42 dirs