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Note also that this does not need any subshells. I think dataflow was thinking of (test -f a && test -f b) || (test -f c && test -f d) instead, but { } isn't wo

• dataflow 6y ago
  Yeah almost. I was thinking of ([ -f a ] && [ -f b ]) || ([ -f c ] && [ -f d ]) instead of (test -f a && test -f b) || (test -f c && test -f d)
  • dolmen 6y ago
    Parentheses launch a subshell, so you probably want to use accolades instead: {[ -f a ] && [ -f b ] ;} || { [ -f c ] && [ -f d ] ;}
    • dataflow 6y ago
      With braces I'd prefer the test syntax actually, this is too many special characters to be comfortably readable for me. And yes I know it creates subshells, that was precisely what I was saying in my comment where I said the simplest syntax I could think of (i.e. that very code) creates subshells.