3 ms·
I suspect the waveform is so non-sinusoidal because the eye is approximately log-sensitive. So if you want something to look sinusoidal, you should really physi
by lutorm 15y ago
I suspect the waveform is so non-sinusoidal because the eye is approximately log-sensitive. So if you want something to look sinusoidal, you should really physically output exp(sin(w*t)+c), which looks approximately like the output on the scope.
- HeyLaughingBoy 15y agoExactly right. A couple years ago someone asked me to build him a product that would simulate sunrise: basically just gradually fade up a few high-power LEDs. The only thing I found that worked was a very gradual logarithmic-type fade. Even so, I had to prolong the curve at the low end. It turns out that human vision can detect small changes at low light levels, but at high brightness it takes a big step change to register. Probably old-hat to trained lighting engineers, but I learned a lot doing such a seemingly simple project.