> COBS first takes its input data and logically appends a single zero byte. (It is not necessary actually to add this zero byte to the end of the packet in memo

> COBS first takes its input data and logically appends a single zero byte. (It is not necessary actually to add this zero byte to the end of the packet in memory; the encoding routine simply has to behave as if the added zero were there.) So it's `02 xx`. By the way, a single zero byte would be `01 01`.