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Yes, that would be actual operator overloading. Personally, I've always wanted languages to be stricter about that kind of thing. It's not that hard to explici
by clhodapp 6y ago
Yes, that would be actual operator overloading.
Personally, I've always wanted languages to be stricter about that kind of thing. It's not that hard to explicitly express the desired conversions to make the types on both sides of your binary math operators the same and it feels a lot more "controlled" to me to do so.