5 ms·
Yes, it’s not hard...I use the reversed digits method: 82F ≈ 28C 61F ≈ 16C 40F ≈ 04C 11F ≈ -11C
by michaericalribo 6y ago
Yes, it’s not hard...I use the reversed digits method:
82F ≈ 28C
61F ≈ 16C
40F ≈ 04C
11F ≈ -11C
- bserge 6y agoFirst time I hear about it, noticed the accuracy drops off significantly if the last number is >1? 51F ~ 15C 52F ~ 25C 59F ~ 95C? Subtract 30, divide by 2 works well enough heh
- michaericalribo 6y agoHa! 59F is a good one :D Yeah, I should have clarified—this works for those specific combinations...it’s mostly a back of the envelope way to orient yourself in the other system.
- nobody9999 6y ago>Subtract 30, divide by 2 works well enough heh That's close enough for most purposes, but (F)5/9-32=(C) provides better precision.
- thiht 6y ago> 82F ≈ 28C 81F ≈ 18C? 83F ≈ 38C? It... Doesn't work?
- u801e 6y agoThe way I do it is count by nines from 32 to get to the temperature I want and then multiply by 5. For example, if I want to know what the corresponding temperature for 70 °F in Celsius, I would do the following: 0 -> 32 5 -> 41 10 -> 50 15 -> 59 20 -> 68 So I know the temperature in Celsius is just above 20 °C (21 °C give or take). To speed up the process, I can use other starting points I know like 10 °C for 50 °F, 35 °C for 95 °F, -15 °C for 5 °F and, of course, at -40, it doesn't matter ;)