2 ms·
Specifically, the JVM knows there are no pointers into the stack because Java and bytecode cannot express: int a = 1; int *b = &a; Or rather, this con
by thu2111 6y ago
Specifically, the JVM knows there are no pointers into the stack because Java and bytecode cannot express:
int a = 1;
int *b = &a;
Or rather, this construct can occur, but it's always the decision of the JIT compiler to emit such code and it is cooperating with the rest of the runtime.