3 ms·
> Still sub-exponential, which is why I’m still optimistic. If you said that about an algorithm you were considering introducing into production code, I'd say
by pmiller2 6y ago
> Still sub-exponential, which is why I’m still optimistic.
If you said that about an algorithm you were considering introducing into production code, I'd say you had a lot of optimization to go. Or, maybe you need to improve your proof. :P
- ben_w 6y ago“Sub-exponential” is a statement of the problem space, the solution is log(n) :P