4 ms·
Or you use -XOverloadedStrings and then you also have in Haskell multiple representations that follow a single polymorphic interface.
by javcasas 6y ago
Or you use -XOverloadedStrings and then you also have in Haskell multiple representations that follow a single polymorphic interface.
- millstone 6y agoIt does not. -XOverloadedStrings unlocks `fromString :: String -> a.` That is not a polymorphic string interface; it's just syntax sugar for making something else from a string literal.