This argument has been argued over and over and the FAQ offers counterarguments [1]. Also if you can build a good lossy compressor it's relatively easy to conve

This argument has been argued over and over and the FAQ offers counterarguments [1]. Also if you can build a good lossy compressor it's relatively easy to convert into a lossless one (residual coding), but the inverse does not hold in general. [1] http://prize.hutter1.net/hfaq.htm#lossless http://prize.hutter1.net/hfaq.htm#lossless