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It really doesn't. Sure the mathematical model you have of a prism might contain terms that the solution is encoded into, but these terms either a) require rapi
by Strilanc 6y ago
It really doesn't. Sure the mathematical model you have of a prism might contain terms that the solution is encoded into, but these terms either a) require rapidly increasing effort to extract from the experiment as the computational problem grows or b) are precisely where the model is diverging from reality (e.g. assuming infinite precision despite physical fuzziness due to effects like finite temperatures and Heisenberg uncertainty).
- adamnemecek 6y agoInfinite or arbitrary precision?
- Strilanc 6y agoThe amount of precision actually required would depend on the size of the problem being solved. But I meant that the mathematical model you had in mind probably just used perfect real numbers without a notion of precision.
- adamnemecek 6y agoIt would not use those no.