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They can't overlap! I don't think the problem specifies that? You have to interpret "break up" to mean "non-overlapping" to claim that the problem means what y
by llimllib 15y ago
They can't overlap! I don't think the problem specifies that?
You have to interpret "break up" to mean "non-overlapping" to claim that the problem means what you're saying it means; I found 341 "contiguous subsequences such that the sums of each of the subsequences are equal", but they overlap.
(If you had said "partition" I suspect I would have got what you meant)
- DanielStraight 15y agoContiguous implies non-overlapping.