3 ms·
It's not b64 encoding the final byte of the hash, not dropping a b64 character.
by daeken 15y ago
It's not b64 encoding the final byte of the hash, not dropping a b64 character.
- StavrosK 15y agoAh, I see. You are correct, then. Also, that would make it 64 times, if I were right, it seems.