4 ms·
What do you mean, "map values"? There is [sin(x) for x in vec] map(sin, vec) sin.(vec) which are roughly equivalent? Is that what you're referring
by ced 6y ago
What do you mean, "map values"? There is
[sin(x) for x in vec]
map(sin, vec)
sin.(vec)
which are roughly equivalent? Is that what you're referring to?
- snicker7 6y agoDon't forget the "lazy" version: (sin(x) for x in vec)