3 ms·
In C++, this may be even worse. Functions int f(int k) { return k+1; } and int f(const int k) { return k-1; } are considered different.
by alexcohn 6y ago
In C++, this may be even worse. Functions
int f(int k) { return k+1; }
and
int f(const int k) { return k-1; }
are considered different.