2 ms·
You’ve got a factor of three sneaking into your 4^4. In general (ab) mod n == (a mod n)(b mod n) mod n In the case of (3*c)^4, 3^4 mod 15 -> 108 mod 15 -> 3.
by ersatz_username 6y ago
You’ve got a factor of three sneaking into your 4^4.
In general (ab) mod n == (a mod n)(b mod n) mod n
In the case of (3*c)^4, 3^4 mod 15 -> 108 mod 15 -> 3.