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With n employees the probability that any given day is a working day is (364/365)^n. So in a year you get 365n(364/365)^n man working days. Maximizing this cont
by jules 15y ago
With n employees the probability that any given day is a working day is (364/365)^n. So in a year you get 365n(364/365)^n man working days. Maximizing this continuously gives uniquely n=364.5, so either n=364 or n=365 is the best we can do. Computing both it turns out it doesn't matter which.
- euroclydon 15y agoI would think the probability that any given day is a work day is ((364/365)(5/7))^n
- jules 15y agoWell, if you're thinking about weekends it is (364/365)^n*5/7, so it doesn't make a difference for the maximum.