4 ms·
Spent a similar amount of time... Ended up with a "solution" that breaks 1 constraint. Must have erred somewhere, but backtracking is only leading to other 1-br
by mypalmike 6y ago
Spent a similar amount of time... Ended up with a "solution" that breaks 1 constraint. Must have erred somewhere, but backtracking is only leading to other 1-broken constraint outcomes. Sigh.
- schoen 6y agoOfficial solution from the original author: https://web.mit.edu/puzzle/www/2013/coinheist.com/rubik/a_regular_crossword/answer/index.html https://web.mit.edu/puzzle/www/2013/coinheist.com/rubik/a_re...
- lkbm 6y agoOooh, I was stuck because I was insisting on `.(1)(2)(3)(4)\4\3\2\1.` having the middle eight characters mirror each other, which results in a clear contradiction with a few of the crosses. Thanks for posting the answers. I think I'm done working on it for now, but that one was really bothering me.
- darkerside 6y agoThis is how I interpret it, too. What am I missing?
- Jimbly 6y agoBecause of the ".*" on either end, it's just having a sequence of 8 somewhere that are mirrored, could be the first 8 or last 8, not strictly the middle 8.
- lkbm 6y agoYeah, sorry for the bad formatting. I probably should've taken the time to make it not markdownify the asterisks. Without them, it is mirroring the middle eight.
- darkerside 6y agoI misread the parent post and I was interpreting the clue correctly after all. Thanks for helping clarify. It was a fun puzzle.
- mypalmike 6y agoWhat's the fun in that? :-P Thanks though. I tried again on my laptop and got it - was a bit easier with a larger display than on my phone.