3 ms·
Assuming base 32 and we have 8char initially. That gives us around 32^8 = 1.099e12 of serial numbers. Might be enough for a while.
by mofosyne 6y ago
Assuming base 32 and we have 8char initially. That gives us around 32^8 = 1.099e12 of serial numbers. Might be enough for a while.