2 ms·
++ can't operate on !good because it's not an lvalue (i.e. not assignable). typedef double winston; winston smith(int good) { return (double)+!good; }
by kps 6y ago
++ can't operate on !good because it's not an lvalue (i.e. not assignable).
typedef double winston;
winston smith(int good) { return (double)+!good; }