3 ms·
I mean, if a copy constructor exists then the other version should obviously also work. But at the same time, it isn't quite how this was meant to be used.
by rocqua 6y ago
I mean, if a copy constructor exists then the other version should obviously also work. But at the same time, it isn't quite how this was meant to be used.
- rq1 6y agoYup indeed. :)