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Not having to build an executable for each target system.
by sime2009 6y ago
Not having to build an executable for each target system.
- mikepurvis 6y agoI think it’s neat how this acknowledges the reality that the actual meat of the machine code is identical for every x86_64 target— all that's different is the OS interface. So unlike other "fat binary" schemes where there's a lot of duplication, this one has a single main program and then small shims to provide the Linux ABI on MacOS and Windows.