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Not only fly but climb. Commercial aircraft are required to fly safely should one of the two engines fail at any point of the flight, including takeoff at spee

by xvf22 6y ago

Not only fly but climb. Commercial aircraft are required to fly safely should one of the two engines fail at any point of the flight, including takeoff at speeds beyond v1.

snuxoll 6y ago
For the uninformed: V1: Speed at which the take off attempt should no longer be aborted Vr: Speed at which the plane should be pitched up (rotated) V2: Speed at which the plane can safely climb with one engine If an engine fails after V1 the runway is supposed to have sufficient length that you can hit Vr, rotate, and be 35 feet off the ground and traveling at V2 before you run out of tarmac even with a single engine.
- xvf22 6y ago
  Fair enough and my memory may be fuzzy but I see quite a few references to V1 as being the minimum single engine takeoff speed. https://skybrary.aero/bookshelf/books/493.pdf https://skybrary.aero/bookshelf/books/493.pdf (page 2)
  - snuxoll 6y ago
    It's kind of poorly worded. Hitting V1 means you are committed to taking off, single engine failure or not - but you HAVE to reach V2 to safely climb on one engine. This should happen within moments of hitting Vr, but being single-engine after V1 means you went from hitting Vr halfway down the runway to potentially doing so at the ass-end of your minimum runway length. This means you have basically no room for any pilot error or other failures, and why engine failure on take-off is routinely rehearsed.
    - xvf22 6y ago
      Not sure where the original disagreement came from. I never said an aircraft should be able to take off at V1. Perhaps you took the "fly" literally which is fine but that was certainly not the intention.
  - zerocrates 6y ago
    I don't have any specialist knowledge here, but that seems to make sense. If you're under V1 then you can still abort takeoff. Having that be the minimum for single-engine takeoff essentially sets up the rule that if you lose an engine while you can safely abort, then you must.

by xvf22 6y ago

Not only fly but climb. Commercial aircraft are required to fly safely should one of the two engines fail at any point of the flight, including takeoff at speeds beyond v1.

snuxoll 6y ago

For the uninformed: V1: Speed at which the take off attempt should no longer be aborted Vr: Speed at which the plane should be pitched up (rotated) V2: Speed at which the plane can safely climb with one engine If an engine fails after V1 the runway is supposed to have sufficient length that you can hit Vr, rotate, and be 35 feet off the ground and traveling at V2 before you run out of tarmac even with a single engine.

xvf22 6y ago
Fair enough and my memory may be fuzzy but I see quite a few references to V1 as being the minimum single engine takeoff speed. https://skybrary.aero/bookshelf/books/493.pdf https://skybrary.aero/bookshelf/books/493.pdf (page 2)
- snuxoll 6y ago
  It's kind of poorly worded. Hitting V1 means you are committed to taking off, single engine failure or not - but you HAVE to reach V2 to safely climb on one engine. This should happen within moments of hitting Vr, but being single-engine after V1 means you went from hitting Vr halfway down the runway to potentially doing so at the ass-end of your minimum runway length. This means you have basically no room for any pilot error or other failures, and why engine failure on take-off is routinely rehearsed.
  - xvf22 6y ago
    Not sure where the original disagreement came from. I never said an aircraft should be able to take off at V1. Perhaps you took the "fly" literally which is fine but that was certainly not the intention.
- zerocrates 6y ago
  I don't have any specialist knowledge here, but that seems to make sense. If you're under V1 then you can still abort takeoff. Having that be the minimum for single-engine takeoff essentially sets up the rule that if you lose an engine while you can safely abort, then you must.