2 ms·
And exponentiating is (relatively) easy beacuse a^(xyz) = ((a^x)^y)^z and as long as you know how to square, you can pretty much compute exponentials in log2(
by pfortuny 6y ago
And exponentiating is (relatively) easy beacuse
a^(xyz) = ((a^x)^y)^z
and as long as you know how to square, you can pretty much compute exponentials in log2(exponent) time.