4 ms·
So our opponents were queueing as individuals and were highly skilled. So their “party Elo” was genuinely 2k. Parties would be selected to take place in a match
by chairmanwow1 6y ago
So our opponents were queueing as individuals and were highly skilled. So their “party Elo” was genuinely 2k. Parties would be selected to take place in a match (2v2 / 3v3 / 4v4) of similar party Elos.
We would either get paired with another couple 2k players against a full team of 2k (4v4 match) or in the worst case a 2v2 against 2k players.
In the 2v2 case, because of the Elo difference the opposing side was expected to win >99.99% of the time.
- bitshiftfaced 6y agoSince there are an equal number of players on both teams, why would it matter if the system used the average or the sum of the players' Elo? Wouldn't both methods have the same outcome?