3 ms·

For 6) itertools.groupby() helps a bit: import itertools passed, failed = (list(v) for k,v in itertools.groupby([49, 58, 76, 82, 88, 90], lambda x: x > 60)

by nuxi 15y ago

For 6) itertools.groupby() helps a bit: import itertools passed, failed = (list(v) for k,v in itertools.groupby([49, 58, 76, 82, 88, 90], lambda x: x > 60))