3 ms·
I don't think I understand how pricing works, but at the most expensive level, it seems to be $15/km^2, so 2 km^2 once a week would be $30/week, right?
by prewett 6y ago
I don't think I understand how pricing works, but at the most expensive level, it seems to be $15/km^2, so 2 km^2 once a week would be $30/week, right?
- Brajeshwar 6y agoI believe, his calculation is roughly at $30 per week x 4 weeks per month x 12 months a year. Anyway, the cost of a 3-meter resolution loaded with multispectral bands and metadata will be just about a dollar per sqkm or even less.