4 ms·
You can arrive at the same by slicing in nearly any manner you wish: vertical dx strips, horizontal dy strips, radial dtheta strips, concentric rings treated as
by ChrisLomont 6y ago
You can arrive at the same by slicing in nearly any manner you wish: vertical dx strips, horizontal dy strips, radial dtheta strips, concentric rings treated as rectangles, diagonal strips, literally anything you wish.
If you've never set up and worked a few, try the dx version and the dy version, then maybe fiddle with a few others. They all work.
The concentric rings one is trivial to work out. Integrate over r from 0 to R. Each ring at radius r has thickness dr, and has length 2 pi r, treated simply as a rectangle, which is "close enough" since each is arbitrarily thin. Then the integral is
int_0^R 2 pi r dr = 2pi r^2/2 from 0 to R = pi R^2.
A really pretty one cuts the circle into wedges, then rearranges them by alternating direction to make a "rectangle" approx r high, approx pi * r wide, with bumpy top and bottom. In the limit this has area pi * r * r, and can be shown to kids without needing calculus.
And it's not magic or circular, since pi is defined (in this case...) as the ratio of circumference to diameter.