3 ms·
If the language doesn't expose pointers, then that's an abstraction leak. Even if it does, why must that dictate the syntax and semantics? I'm sure our compiler
by andreareina 6y ago
If the language doesn't expose pointers, then that's an abstraction leak. Even if it does, why must that dictate the syntax and semantics? I'm sure our compilers and interpreters are capable of turning
arr[i]
into
*arr + (i + 1)