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Very interesting that a read operation manages to corrupt the index. That makes it likely that it causes an overflow or similar memory corruption in an unfortu
by t0mas88 6y ago
Very interesting that a read operation manages to corrupt the index. That makes it likely that it causes an overflow or similar memory corruption in an unfortunate place while reading. For example allocating a buffer based on the literal length of that path and then later expanding the variable?
- uncledave 6y agoI’m not sure it actually does corrupt anything. I just spent an hour on this and it never manifests itself as any actions performed via chkdsk. I think it might just trigger a mandatory consistency check.