Good point about symmetry & unimodality. You could easily construct a bimodal example where the method fails entirely. In my previous post I said "doesn't ass

Good point about symmetry & unimodality. You could easily construct a bimodal example where the method fails entirely. In my previous post I said "doesn't assume any distribution" I meant it doesn't depend on any particular distribution function. But in the post above that I was sloppy and said "no assumptions about the distribution at all". Good catch.