3 ms·
+1, by personal experience, O(n log(n)) sounds about right. (Actually, n log(n) + a constant offset; i.e. partitioning the code has its limits where it becomes
by eqvinox 6y ago
+1, by personal experience, O(n log(n)) sounds about right.
(Actually, n log(n) + a constant offset; i.e. partitioning the code has its limits where it becomes detrimental.)