3 ms·
The trivial implementation isn't law abiding. This law doesn't hold (written in Kleisli form for simplicity) pure >=> f == f (left identity) There are no
by tel 6y ago
The trivial implementation isn't law abiding. This law doesn't hold (written in Kleisli form for simplicity)
pure >=> f == f (left identity)
There are no other monads for Maybe. First, any definition of pure must be Just as Nothing doesn't work because of left identity and parametricity prevents any other funny business. Now, by law we know
pure a >>= f == f a
Thus, we must define
Just a >>= f = f a
So the only variable is what (Nothing >>= f) does. For (f: A -> B) we must end up with a Maybe B. We don't have one to start and we can produce Maybe values only via Nothing and Just. So, either >>= is the standard definition or we have to do
Nothing >>= f = Just (_: B) -- we can achieve a B only via use of f, so
Nothing >>= f = Just (f (_: A)) -- now we are stuck, there are no values of A
Thus, we must define
pure a = Just a
Just a >>= f = f a
Nothing >>= f = Nothing
- uryga 6y agoyeah, and as others pointed out it fails right-identity as well. had a brain fart recapping the laws, though i think i got associativity right at least!