3 ms·
Well I guess they're assuming the operators are more physical than theoretical and they should conserve things (so I think they're limited to hermitian operator
by contravariant 6y ago
Well I guess they're assuming the operators are more physical than theoretical and they should conserve things (so I think they're limited to hermitian operators). But yeah that sounds about right.
Not that I mind that they're looking for a different foundation but you can't just gloss over the problem of explaining statistical physics without statistics...