3 ms·

The basic idea is that you cannot "implement" (emulate) memristance using resistors, capacitors and inductors and that is what causes it to be fundamental prope

The basic idea is that you cannot "implement" (emulate) memristance using resistors, capacitors and inductors and that is what causes it to be fundamental property of the circuit element.

contravariant 6y ago
Since memristance is just the charge-dependent flux I'm not sure you couldn't get it by just throwing a resistor capacitor and inductor into a single circuit. In fact memristance is just the voltage divided by the current, which is impossible to be 0 for any circuit with some voltage. So by this definition almost any circuit has memristance. Note that it's not unfair to consider any circuit with nonzero memristance as 'containing' a memristor, after all the whole point of fundamental circuit elements is that you can add them to model stuff like wire resistance and stray capacitance. However while you can't create resistance, capacitance and inductance by combining any of the others you can have memristance by combining all 3 (technically you can create any of the 4 by combining the 3 others, but 3 of them can be built easily so those make more sense as fundemental circuit elements). So while a linear memristor would be rather unusual, I don't quite see what's so fundamental about it as a non-linear circuit element.
- lmilcin 6y ago
  > In fact memristance is just the voltage divided by the current In fact, voltage divided by current is resistance, BY DEFINITION. Hey, you can also take a bunch of resistors, wire them in a loop and proclaim you have successfully emulated inductor with just resistors. That is what you get if you decide to set aside rules. Important part of the description of what is memristor is its dependence on past charge flown through it, you can't decide to ignore parts of definition whenever it suits your argument.
  - contravariant 6y ago
    >In fact, voltage divided by current is resistance, BY DEFINITION. For a linear resistor sure, but otherwise resistance is better defined as the slope. And well if you don't like that definition of memristance I suggest you update the corresponding wikipedia article. > Hey, you can also take a bunch of resistors, wire them in a loop and proclaim you have successfully emulated inductor with just resistors. That is what you get if you decide to set aside rules. A circle of resistors has 0 inductance by definition. In practice it's pretty tricky to build such a circuit using 0 inductance wire in an impermeable environment so it remains an approximation.
- dr_dshiv 6y ago
  Key to a memristor is hysteresis -- the cycling of resistance, based on past current. This makes them fundamentally oscillatory.

The basic idea is that you cannot "implement" (emulate) memristance using resistors, capacitors and inductors and that is what causes it to be fundamental property of the circuit element.

contravariant 6y ago

Since memristance is just the charge-dependent flux I'm not sure you couldn't get it by just throwing a resistor capacitor and inductor into a single circuit. In fact memristance is just the voltage divided by the current, which is impossible to be 0 for any circuit with some voltage. So by this definition almost any circuit has memristance. Note that it's not unfair to consider any circuit with nonzero memristance as 'containing' a memristor, after all the whole point of fundamental circuit elements is that you can add them to model stuff like wire resistance and stray capacitance. However while you can't create resistance, capacitance and inductance by combining any of the others you can have memristance by combining all 3 (technically you can create any of the 4 by combining the 3 others, but 3 of them can be built easily so those make more sense as fundemental circuit elements). So while a linear memristor would be rather unusual, I don't quite see what's so fundamental about it as a non-linear circuit element.

lmilcin 6y ago
> In fact memristance is just the voltage divided by the current In fact, voltage divided by current is resistance, BY DEFINITION. Hey, you can also take a bunch of resistors, wire them in a loop and proclaim you have successfully emulated inductor with just resistors. That is what you get if you decide to set aside rules. Important part of the description of what is memristor is its dependence on past charge flown through it, you can't decide to ignore parts of definition whenever it suits your argument.
- contravariant 6y ago
  >In fact, voltage divided by current is resistance, BY DEFINITION. For a linear resistor sure, but otherwise resistance is better defined as the slope. And well if you don't like that definition of memristance I suggest you update the corresponding wikipedia article. > Hey, you can also take a bunch of resistors, wire them in a loop and proclaim you have successfully emulated inductor with just resistors. That is what you get if you decide to set aside rules. A circle of resistors has 0 inductance by definition. In practice it's pretty tricky to build such a circuit using 0 inductance wire in an impermeable environment so it remains an approximation.
dr_dshiv 6y ago
Key to a memristor is hysteresis -- the cycling of resistance, based on past current. This makes them fundamentally oscillatory.