4 ms·

Or simply: cell.live = count is 3 no?

• ggchappell 15y ago
  No. You aren't handling the case when count is 2 correctly. In that case, cell.live should remain unchanged, while you are setting it to false. (Note, however, that the code in the comment you are replying to is also incorrect. And does the same thing as your code. So you posted a correct transformation of incorrect code, that keeps it incorrect.)
  • abarrett 15y ago
    The original version still contains redundancy. It would be: cell.live = count == 3 if count != 2
    • ggchappell 15y ago
      Yes, that would do it.