3 ms·
You can, but you can't (currently?) do =A1(x) where A1 is a LAMBDA function. I think LAMBDA(...)(x) is only useful for testing/development, but maybe I'm missin
by ripley12 6y ago
You can, but you can't (currently?) do =A1(x) where A1 is a LAMBDA function. I think LAMBDA(...)(x) is only useful for testing/development, but maybe I'm missing some good use cases.
- contravariant 6y agoIf need be you could always just define a lisp interpreter.