3 ms·
I found my first substantive error in upwards of 5 minutes. On page 3, he claims that if gcd(A,B)=gcd(B,C)=gcd(C,A)=1 then gcd(C-A, C-B)=1, which is clearly fa
by shasta 15y ago
I found my first substantive error in upwards of 5 minutes. On page 3, he claims that if gcd(A,B)=gcd(B,C)=gcd(C,A)=1 then gcd(C-A, C-B)=1, which is clearly false (take A,B,C = 3,7,11 for example). His "proof" shows only that gcd(A+B, C-A, C-B)=1. It sounds like this is an important lemma for his proof, but it hardly seems worth the extra minutes I'd need to spend reading to find out. There're no doubt bigger problems further in.