4 ms·

Related video by 3Blue1Brown: https://youtu.be/EOtduunD9hA https://youtu.be/EOtduunD9hA EDIT: correct link below.

• skovorodkin 6y ago
  "This is the corrected version of the one I put out a month or so ago, in which my animation for all the inverse operations was incorrect": https://www.youtube.com/watch?v=sULa9Lc4pck https://www.youtube.com/watch?v=sULa9Lc4pck.
• kortex 6y ago
  This really hammers home the advantage of this notation. It leads naturally to the question, "What is the operation when we leave the bottom right constant?" which Grant calls "O-plus" (tex call it \oplus), which is in fact related to the harmonic mean (which is n times the o-plus of the terms). I don't know if there's a better term for "o-plus" other than "reciprocal sum of reciprocals". Maybe "optical sum" which kind of makes o-plus make even more sense? https://en.wikipedia.org/wiki/Optic_equation https://en.wikipedia.org/wiki/Optic_equation https://en.wikipedia.org/wiki/List_of_sums_of_reciprocals https://en.wikipedia.org/wiki/List_of_sums_of_reciprocals
  • multidim 6y ago
    > which is in fact related to the harmonic mean (which is n times the o-plus of the terms). I don't know if there's a better term for "o-plus" other than "reciprocal sum of reciprocals" I would call it the "harmonic norm", which is consistent with is being the "norm version" of the harmonic mean. It might also be called the "(p=-1) norm" since it would be a p-norm with p=-1. Also "L-1 norm" to put it in the "L norm" family. https://en.wikipedia.org/wiki/Norm_(mathematics)#p-norm https://en.wikipedia.org/wiki/Norm_(mathematics)#p-norm