7 ms·
It definitely doesn't go undetected, as the conflicting transactions would have to be in blocks both forking from a common block, both signed by the attacker, w
by everfree 6y ago
It definitely doesn't go undetected, as the conflicting transactions would have to be in blocks both forking from a common block, both signed by the attacker, which is a slashing condition that would burn their staked ether.