4 ms·
Jason Crawford answers your question here: https://twitter.com/jasoncrawford/status/1333576261877125121?s=19 https://twitter.com/jasoncrawford/status/1333576261
by MarkMc 6y ago
Jason Crawford answers your question here: https://twitter.com/jasoncrawford/status/1333576261877125121?s=19 https://twitter.com/jasoncrawford/status/1333576261877125121...
Short answer: it's extremely computationally expensive