3 ms·
Likewise for auto_ptr<T>, but he glosses over that.
by ezy 15y ago
Likewise for auto_ptr<T>, but he glosses over that.
- shasta 15y agoHow do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.
- obiterdictum 15y agoThere isn't. There are two explicit methods to get raw pointer value with different semantics: - get(): auto_ptr retains the ownership - release(): auto_ptr loses the ownership