3 ms·
I failed to add that the stores aren't eliminated by this either so we are also incurring increased memory traffic unnecessarily.
by FullyFunctional 6y ago
I failed to add that the stores aren't eliminated by this either so we are also incurring increased memory traffic unnecessarily.
- jcranmer 6y agoWe're talking about stores to the stack, which is likely to not be used by other threads/processors, so all of the values are being modified in a cache entry helpfully held in the Modified state and incurring no bus traffic. It will use up the traffic to/from the cache, though.
- FullyFunctional 6y agoYes I did mean cache traffic, poor choice of words, but the point is the same (filling up the store buffers etc).