3 ms·
Note that this isn't guaranteed to be a no-op for arbitrary "all the stuff". Specifically it won't work for commands involving pipes, or commands involving comm
by Arnavion 6y ago
Note that this isn't guaranteed to be a no-op for arbitrary "all the stuff". Specifically it won't work for commands involving pipes, or commands involving command substitution / process substitution. That is:
: bar "$(foo)"
: bar <(foo)
: < <(foo) bar
: bar | foo
will all still execute `foo`
- kps 6y agoThat's why I mentioned quoting.