Whoops, I wrote that far too late last night. 15&15 = 15, so of course it wouldn't work :) A 2,8-fizzbuzz would only need 8 items in the circular array since t

Whoops, I wrote that far too late last night. 15&15 = 15, so of course it wouldn't work :) A 2,8-fizzbuzz would only need 8 items in the circular array since the least common multiple of 2 and 8 is 8: ix = ix & 8;